[cryptography] cryptanalysis of 923-bit ECC?
Matthew Green
matthewdgreen at gmail.com
Wed Jun 20 11:35:07 EDT 2012
I'm definitely /not/ an ECC expert, but this is a pairing-friendly curve, which means it's vulnerable to a type of attack where EC group elements can be mapped into a field (using a bilinear map), then attacked using an efficient field-based solver. (Coppersmith's).
NIST curves don't have this property. In fact, they're specifically chosen so that there's no efficiently-computable pairing.
Moreover, it seems that this particular pairing-friendly curve is particularly tractable. The attack they used has an estimated running time of 2^53 steps. While the 'steps' here aren't directly analogous to the operations you'd use to brute-force a symmetric cryptosystem, it gives a rough estimate of the symmetric-equivalent key size.
(Apologies to any real ECC experts whose work I've mangled here… :)
Matt
On Jun 20, 2012, at 10:59 AM, Charles Morris wrote:
> "NIST guidelines state that ECC keys should be twice the length of
> equivalent strength symmetric key algorithms."
> So according to NIST solving a 923b ECC is like brute-forcing a 461b
> bit symmetric key (I assume in a perfect cipher?).
>
> Of course there are weak keys in almost any system e.g. badly
> implemented RSA picking p=q
>
> I wonder if a weak-key scenario has occurred, or if this is a genuine
> generalized mathematical advance?
> Comments from ECC experts?
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